A line passing through `(0,0)` and perpendicular to `2x+y+6=0,4x+2y-9=0` then the origin divids the line in the ratio of

A : Equation of the line passing through (3, -4) and perpendicular to 2x+3y+7=0 is 3x-2y-17=0 . R : Equation of the line passing through (x_(1), y_(1)) and perpendicular to ax+by+c=0 is b(x-x_(1))-a(y-y_(1))=0

Equatin of the line passing through (-1, 1) and perpendicular to the line 2x +3y +4 =0 is

Equatin of the line passing through (-1, 1) and perpendicular to the line 2x +3y +4 =0 is

A line passing through origin and is perpendicular to two given lines 2x+y+6=0 and 4x+2y-9=0 . The ratio in which the origin divides this line is

A line passing through the points (a, 2a) and (-2, 3) is perpendicular to the line 4x+3y+5=0 , then the value of a is

The equatin of a line passing through the origin and perpendicular to the line 7x-3y+4=0 is

The equation of a line passing through the origin and perpendicular to the line 7x-3y+4=0 is ……..