in the diagram O is the centre of a circle. `AE + EB = CE + ED. OP _|_ AB and OQ_|_ CD`,then true relation between OP and OQ is:

In the given figure, O is the centre of the circle. If chord AB= chord AC, OP bot AB and OQ bot AC , show that: PB= QC

In the figure O is the centre of a circle of radius 29 cm OP_|_AB,OQ_|_CQ and AB is parallel CD. If AB=40cm and CD=42cm, then the length of PQ is

In the figure, O is the centre of the circle of radius 29 cm, OP bot AB, OQ bot CD and AB is parallel to CD. If AB = 40 cm and CD = 42 cm, then the length of PQ is: दी गयी आकृति में, O वृत्त का केंद्र है जिसकी त्रिज्या 29 सेमी है , OP bot AB, OQ bot CD और AB, CD के समान्तर है। यदि AB= 40 सेमी और CD = 42 सेमी है, तो PQ की लंबाई है

In Figure,O is the centre of the circle of radius 5cmdot OP+AB,OQ perp CD,ABCD,AB=6cm and CD=8cm Determine PQ.

In the figure, O is the centre of a circle and diameter AB bisects the chord CD at a point E such that CE = ED = 8 cm and EB = 4 cm. The radius of the circle is . . . . .

In Figure,O is the centre of the circle of radius 5cmOP perp AB,OQ perp CD,ABCD,AB=6cm and CD=8cm Determine PQ

Two tangents PA and PB are drawn from a point P to the circle. If the radius of the circle is 5 cm and AB = 6 cm and O is the centre of the circle. OP cuts AB at C and OC = 4 cm, then OP :-

OP……...OQ, where O is the centre of the circle, P lies on the circle and Q is in the interior of the circle.