In the figure, BC is a chord of the circle with centre o and A is a point on the minor are BC. Then `/_ABC-/_OBC `is equal to

In the figure AB is the chord of a circle with centre O and DOC is a line segment such that BC=DO . If /_C=20^(@) , find angle AOD.

BC is a chord with centre O. A is a point on an arc BC . Prove that: ∠BAC−∠OBC= 90^@ .

In the figure, O is the center of the circle and BO is the bisector of /_ ABC show that AB=BC

In the figure,O is the center of the circle and BO is the bisector of angle ABC show that AB=BC

In the given figure,AB and BC are two chords of the circle with Centre O ,where /_BAO=50^(@),/_BCO=35^(@) ,then /_AOC is equal to

In Figure,BC is a tangent to the circle with centre O CE bisects AP. Prove that AEO-ABC.

BC is a chord to a circle with centre O. A is a point on major are BC as shown in the below figure. What is the value of angle BAC + angle OBC ?

in the given figure, AB and BC are two chords of the circle with Centre O, where /_BAO = 50°, /_BCO = 35°, then /_AOC is equal to A)170° b)70° c)150° d)None of these

In the given figure,AB and AC are two equal chords of a circle with centre O.Show that o lies on the bisectors of /_BAC.