[" 4.A particle starts moving rectilinearly at time "t=0" such that its velocity "v" changes with time "],[t" according to the equation "v=t^(2)-t" where "t" is in seconds and "v" is in "m/s" .The time interval "],[" for which the particle retards is "],[[" (a) "t<1/2," (b) "1/21," (d) "t<1/2" and "t>1]]

A particle starts moving rectillineraly at time t = 0 , such that its velocity 'v' changes with time 't' according to the equation v = t^(2) -t where t is in seconds and v is in m//s . The time interval for which the particle retards is

A particle starts moving rectilinearly at time t=0 such that its velocity v changes with time t according to the equation v=t^(2)-t , where t is in seconds and v in s^(-1) . Find the time interval for which the particle retards.

A particle starts moving rectilinearly at time t=0 such that its velocity v changes with time t according to the equation v=t^(2)-t , where t is in seconds and v in s^(-1) . Find the time interval for which the particle retards.

A particle starts moving rectilinearly at time t = 0 such that its velocity v changes with time t according to the equation v = t^2-t , where t is in seconds and v is in m s^(-1) . The time interval for which the particle retrads (i.e., magnitude of velocity decreases)is

A particle moving in a straight line has its velocit varying with time according to relation v = t^(2) - 6t +8 (m//s) where t is in seconds. The CORRECT statement(s) about motion of this particle is/are:-

A particle moving in a straight line has its velocit varying with time according to relation v = t^(2) - 6t +8 (m//s) where t is in seconds. The CORRECT statement(s) about motion of this particle is/are:-

A particle moving in a straight line has its velocit varying with time according to relation v = t^(2) - 6t +8 (m//s) where t is in seconds. The CORRECT statement(s) about motion of this particle is/are:-

A particle starts moving rectilinearly at time t = 0 such that its velocity(v) changes with time (t) as per equation – v = (t2 – 2t) m//s for 0 lt t lt 2 s = (–t^(2) + 6t – 8) m//s for 2 le te 4 s (a) Find the interval of time between t = 0 and t = 4 s when particle is retarding. (b) Find the maximum speed of the particle in the interval 0 le t le 4 s .

Velocity of a particle of mass 2kg varies with time t according to the equation vec(v)=(2thati+4hatj) m//s . Here t is in seconds. Find the impulse imparted to the particle in the time interval from t=0 to t=2s.

A particle is moving along x-axis such that its velocity varies with time according to v=(3m//s^(2))t-(2m//s^(3))t^(2) . Find the velocity at t = 1 s and average velocity of the particle for the interval t = 0 to t = 5 s.