|x+2|^(2)+|x-2|-2=0

The product of all the solutions of the equation (x-2)^(2)-3|x-2|+2=0 is

The product of all the solutions of the equation (x-2)^(2)-3|x-2|+2=0 is

The product of all the solutions of the equation (x-2)^(2)-3|x-2|+2=0 is

The product of all the solutions of the equation (x-2)^(2)-3|x-2|+2=0 is

The product of all the solutions of the equation (x-2)^(2)-3|x-2|+2=0 is

The product of the roots of the equation (x-2)^(2) -3|x-2|+2 = 0 , is

If the lines 2x+3y+1=0 and 3x-y-4=0 lie along diameters of a circle of circumference 10 pi ,then the equation of the circle is (A) x^(2)+y^(2)-2x+2y-23=0 (B) x^(2)+y^(2)+2x-2y-23=0 (C) x^(2)+y^(2)+2x+2y-23=0 (D) x^(2)+y^(2)-2x-2y-23=0

The normal to the circle x^(2) + y^(2) -2x -2y = 0 passing through (2,2) is

The lines 2x-3y=5 and 3x-4y=7 are the diameters of a circle of area 154 sq. units. Then the equation of the circle is a. x^(2)+y^(2)+2x-2y-62=0 b. x^(2)+y^(2)+2x-2y-47=0 c. x^(2)+y^(2)-2x+2y-62=0 d. x^(2)+y^(2)-2x+2y-47=0