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" The given expression wherever defined ...

" The given expression wherever defined simplifies to "(cos theta)/(sin(90^(@)+theta))-(sin(-theta))/(sin(180^(@)+theta))+(tan(90^(@)+theta))/(cot(-theta))

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Prove that (cos theta)/(sin(90^(@)+theta))+(sin(-theta))/(sin(180^(@)+theta))-(tan(90^(@)+theta))/(cot(theta))=3

Simplify: (i) (cos theta)/(sin (90^@ + theta)) + (sin (-theta))/(sin(180^(@) + theta)) - (tan(90^(@)+theta))/(cot theta)

Simplify : (cos(-theta))/(sin (90^(@)+theta))

Find the value of (sin theta)/(cos (90^@+theta))+(sin theta)/(sin (180^@+theta))+(tan(90^@+theta))/(cot theta)

(sin(90^(@)-theta)sec(180^(@)-theta)sin(-theta))/(sin(180^(@)+theta)cot(360^(@)-theta)"cosec"(90^(@)+theta)) .

((cos (90 ^ (@)) - theta) sin (90 ^ (@) - theta)) / (tan (90 ^ (@) - theta))

(cos(90^(@)-theta).sec(90^(@)-theta).tantheta)/(cosec(90^(@)-theta).sin(90^(@)-theta).cot(90^(@)-theta))=?

sin(270^(@)-theta).sin(90^(@)-theta)-cos(270^(@)-theta).cos(90^(@)+theta)=

sin theta cos(90^(@)-theta)+cos theta sin(90^(@)-theta)