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`(dy)/(dx)+ycotx=2x+x^(2)cotx,` जब y(0)=0

(dy)/(dx) + ycotx = 2cos x

x(dy)/(dx)+y=3x^(2)-2,x>0

Solve: (dy)/(dx)+2ycotx=3x^2cosec^2x

Solve: (dy)/(dx)+2ycotx=3x^2cosec^2x

(dy)/(dx)+(x-2y)/(2x-y)=0

Solve : dy/dx+y cot x = 2x + x^(2) cot x , given that y(0)= 0

Solve sin^(2)x. (dy)/(dx) +y=cotx

Solve : dy/dx+2ycotx=3x^(2)"cosec"^(2)x .

Find dy/dx if y= x.cotx

Find the particular solution of the differential equation (dy)/(dx)+ycotx=2x+x^(2)cotx , it is given that at x=pi//2 , y=0