एक चतुर्भुज ABCD में सिद्ध कीजिए कि -
`vec (AB)+vec(DC)=vec(AC )+vec (DB)`

If ABCD is a quadrilateral, then vec(BA) + vec(BC)+vec(CD) + vec(DA)=

ABCD is a quadrilateral whose diagonals are AC and BD.Which one of the following is correct? (a) vec BA + vec CD = vec AC + vec DB (b) vec BA + vec CD = vec BD + vec CA (c) vec BA + vec CD = vec AC + vec BD (d) vec BA + vec CD = vec BC + vec AD

In Fig. ABCDEF is a ragular hexagon. Prove that vec(AB) +vec(AC) +vec(AD) +vec(AE) +vec(AF) = 6 vec(AO) .

In /_\ABC whch of the folloiwng is not true? vec(AB)+vec(BC)+vec(CA)=0 (A) vec(AB)+vec(BC)+vec(CA)=0 (B) vec(AB)+vec(BC)-vec(AC)=0 (C) vec(AB)+vec(BC)-vec(CA)=0 (D) vec(AB)-vec(CB)+vec(CA)=0

If A, B, C and D aare four points and vec AB = vec DC then vec AC + vec BD =

ABCDE is a pentagon prove that vec(AB)+vec(BC)+vec(CD)+vec(DE)+vec(EA)=vec0

If ABCD is a parallelogram, then vec(AB)+vec(AD)+vec(CB)+vec(CD) is equal to

If ABCDE is a pentagon, then vec(AB) + vec(AE) + vec(BC) + vec(DC) + vec(ED) + vec(AC) is equal to

If ABCDE is a pentagon, then vec(AB) + vec(AE) + vec(BC) + vec(DC) + vec(ED) + vec(AC) is equal to