The emf and current in a circuit are such that `E = E_(0) sin omega t` and `I - I_(0) sin (omega t - theta)`. This `AC` circuit contains

The voltage and current in an a.c. circuit are given by E = 300 sin (omega t + pi//2) and I = 5 sin omega t . What is power factor of the circuit and power dissipated in each cycle ?

The instantaneous values of emf and the current in a series ac circuit are - E = Eo Sin omega t and l = lo sin (omega t + pi //3) respectively, then it is

In any AC circuit the emf (e) and the current (i) at any instant are given respectively by e= E_(0)sin omega t i=I_(0) sin (omegat-phi) The average power in the circuit over one cycle of AC is

In any AC circuit the emf (e) and the current (i) at any instant are given respectively by e= V_(0)sin omega t i=I_(0) sin (omegat-phi) The average power in the circuit over one cycle of AC is

What is power dissipation in an a.c. circuit in which E = 230 sin (omega t + pi//2) , I = 10 sin omega t ?