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(329)/(400)...

(329)/(400)

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Write the equivalent fractions : (250)/(400)

The rational numbers lying between (1)/(3) and (3)/(4) are (117)/(300),(287)/(400) (b) (95)/(300),(301)/(400) (c) (99)/(300),(301)/(400) (d) (97)/(300),(299)/(500)

Solve (?)/(529)=(329)/(?) (a) 404 (b) 408 (c) 410 (d) 414( e) 416

The value of sum_(r=0)^(20)r(20-r)(^(20)C_(r))^(2) is equal to 400^(39)C_(20) b.400^(40)C_(19) c.400^(39)C_(19) d.400^(38)C_(20)

The value of sum_(r=0)^(20)r(20-r) (.^(20) C_r)^2 is equal to a. 400^(39)C_(20) b. 400^(40)C_(19) c. 400^(39)C_(19) d. 400^(38)C_(20)

The value of sum_(r=0)^(20)r(20-r) (.^(20) C_r)^2 is equal to a. 400^(39)C_(20) b. 400^(40)C_(19) c. 400^(39)C_(19) d. 400^(38)C_(20)

The value of sum_(r=0)^(20)r(20-r)(^(20)C_r)^2 is equal to 400^(39)C_(20) b. 400^(40)C_(19) c. 400^(39)C_(19) d. 400^(38)C_(20)

The last two digits of 3^(400) is

Find the centroid of the triangle whose vertices are (3,6,5) (6,2,7) and (3,2,9)