Initially 0.4 mole of `N_(2)` and 0.9 mole of `O_(2)` were mixed then moles of `N_(2),O_(2)` and NO at equilibrium are (approximate):

When a mixture of 10 moles of SO_(2) and 16 moles of O_(2) were passed over a catalyst, 8 moles of SO_(3) were formed at equilibrium. The number of SO_(2) and O_(2) remaining unreacted were:

1 mole of N_(2) and 3 mole of H_(2) are mixed in a closed vessel of 1 dm^(3) capacity. At equilibrium if the vessel contains a total of 2.4 moles, calculate equilibrium constant K_(c)" for "N_(2)+3H_(2)hArr2NH_(3) .

n mole of He and 2n mole of O_2 is mixed in a container. Then (C_p/C_v)_(mix) will be

n mole of He and 2n mole of O_2 is mixed in a container. Then (C_p/C_v)_(mix) will be

One mole of H_(2) and 2 moles of I_(2) are taken initially in a two litre vessel. The number of moles of H_(2) at equilibrium is 0.2. Then the number of moles of I_(2) and HI at equilibrium is

One mole of H_(2) and 2 moles of I_(2) are taken initially in a two litre vessel. The number of moles of H_(2) at equilibrium is 0.2. Then the number of moles of I_(2) and HI at equilibrium is

How many moles of NaOH are required to react with one mole of solid N_(2)O_(5) ?

How many moles of NaOH are required to react with one mole of solid N_(2)O_(5) ?