Wave equations of two particles are given by `y_(1)=a sin (omega t -kx), y_(2)=a sin (kx + omega t)`, then

Equation of motion in the same direction is given by y_(1) =A sin (omega t - kx), y_(2) = A sin ( omega t - kx- theta ) . The amplitude of the medium particle will be

Equation of motion in the same direction is given by y_(1) =A sin (omega t - kx), y_(2) = A sin ( omega t - kx- theta ) . The amplitude of the medium particle will be

Equation of motion in the same direction are given by ltbygt y_(1)=2a sin (omega t-kx) and y_(2)=2a sin (omega t-kx - theta ) The amplitude of the medium particle will be

Equation of motion in the same direction are given by ltbygt y_(1)=2a sin (omega t-kx) and y_(2)=2a sin (omega t-kx - theta ) The amplitude of the medium particle will be

Two waves are given by y_(1) = a sin (omega t - kx) and y_(2) = a cos (omega t - kx) . The phase difference between the two waves is

Equations of two light waves are y_(1) = 4 sin omega t and y_(2) = 3 sin (omega t + (pi)/(2)) . What is the amplitude of the resultant wave as they superpose on each other?

Three waves y_(1), y_(2) ,y_(3) are given by y_(1)= A sin (Kx- omegat), y_(2) A= sin (Kx+ omega t) and y_(3) = A sin (Ky- omega t) . Which one of the following represents wave ?

On the superposition of the two waves given as y_1=A_0 sin( omegat-kx) and y_2=A_0 cos ( omega t -kx+(pi)/6) , the resultant amplitude of oscillations will be