Light of wavelength 330nm falling on a piece of metal ejects electrons with sufficient energy with required voltage `V_0` to prevent them reaching a collector. In the same set up, light of wavelength 220 nm ejects electrons which require twice the voltage `V_0` to stop them in reaching a colleator. the numerical value of voltage `V_0` is

Photon of 5.5 eV energy fall on the surface of the metal emitting photoelectrons of maximum kinetic energy 4.0 eV . The stopping voltage required for these electrons are

Photons of 5.5 eV energy fall on the surface of the metal emitting photoelectrons of maximum kinetic energy 4.0 eV. The stopping voltage required for these electrons is

When a metal surface is illuminated by a monochromatic light of wave-length lambda , then the potential difference required to stop the ejection of electrons is 3V . When the same surface is illuminated by the light of wavelength 2lambda , then the potential difference required to stop the ejection of electrons is V . Then for photoelectric effect, the threshold wavelength for the metal surface will be

When a metal surface is illuminated by a monochromatic light of wave-length lambda , then the potential difference required to stop the ejection of electrons is 3V . When the same surface is illuminated by the light of wavelength 2lambda , then the potential difference required to stop the ejection of electrons is V . Then for photoelectric effect, the threshold wavelength for the metal surface will be

A metal is irradiated with light of wavelength 600 nm. Given that the work function of the metal is 1.0 eV, the de Broglie wavelength of the ejected electron is close to:

A metal is irradiated with light of wavelength 660 nm. Given that the work function of the metal is 1.0eV, the de Broglie wavelength of the ejected electron is close to-

Energy required to remove an electron from aluminium surface is 4.3 V. If light of wavelength 2000 Å falls on the surface, the velocity of the fastest electron ejected from the surface will be