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The x-z plane separates two media A and ...

The x-z plane separates two media A and B of refractive indices `mu_(1)=1.5` and `mu_(2)=2`. A ray of light travels from A to B its direction in the two media are given by unit vectors `vec(u)_(1)=a hat(i) + b hat(j)` and `vec(u)_(2)= chat(i)+dhat(j)` Then

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The x-z plane separates two media A and B of refractive indices mu_(1) = 1.5 and mu_(2) = 2 . A ray of light travels from A to B. Its directions in the two media are given by unit vectors u_(1) = a hat(i)+b hat(j) and u_(2) = c hat(i) +a hat(j) . Then

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The xz plane separates two media A and B with refractive indices mu_(1) & mu_(2) respectively. A ray of light travels from A to B . Its directions in the two media are given by the unut vectors, vec(r)_(A)=a hat i+ b hat j & vec(r)_(B) alpha hat i + beta hat j respectively where hat i & hat j are unit vectors in the x & y directions. Then :

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Two thin slabs of refractive indices mu_(1) and mu_(2) are placed parallel to each other in the x-z plane. If the direction of propagation of a ray in the two media are along the vectors vec(r)_(1) = a hati +b hatj and vec(r)_(2) = c hati +d hatj then we have: