If `A^(-1)=[(1,-1,2),(0,3,1),(0,0,-1//3)]`, then

If A=[(0,1,0),(-1,0,2),(0,0,1)] , then show that A^3-A^2+I_3=[(2,-1,0),(1,2,-1),(0,0,1)]

If A[(1, 0, 0),(x, 1, 0),(x, x, 1)] and I=[(1, 0, 0),(0,1,0),(0,0,1)] , then A^(3)-3A^(2)+3A is equal to

If A=[(2,3,1),(0,-1,5)],B=[(1,2,-1),(0,-1,3)] then 2A-3B=

If A=[(0,1,-2),(-1,0,3),(2,-3,0)] then A+A^(T)=

[(1,3,-2),(-3,0,-5),(2,5,0)] =A [(1,0,0),(0,1,0),(0,0,1)] then, C_(2) rarr C_(2)-3C_(1) and C_(3) rarr C_(3) +2C_(1) gives... [(1,0,0),(3,-9,11),(-2,1,4)] =A [(-1,3,2),(0,-1,0),(0,0,-1)] [(1,0,0),(-3,-1,-4),(2,-9,11)] =A [(1,-3,2),(0,1,0),(0,0,1)] [(1,0,0),(-3,1,4),(-2,9,-11)] =A [(-1,3,2),(0,-1,0),(0,0,-1)] [(1,0,0),(-3,9,-11),(2,-1,4)] =A [(1,-3,2),(0,1,0),(0,0,1)]

If A={:[(3,2,7),(1,1,4),(-1,-1,0)]:},B={:[(1,0,3),(2,1,0),(0,-1,-3)]:}andC{:[(1,0,0),(0,1,0),(0,0,1)]:} , then find 2A+3B-7C.

If A=[(1,0,2),(0,1,2),(1,2,0)],B=[(1,-2,3),(2,3,-1),(-3,1,2)] then

If A=[[1, -1, 2], [3, 0, -2], [1, 0, 3]] , then (adjA)A=