The temperature of the body is increased from `-73^(@)C` to `357^(@)C`, the ratio of energy emitted per second is

The temperature of a body is increased from − 73^(@)C" to "327^(@)C . Then the ratio of emissive power is

The temperature of a black body is increased from 7^(@)C to 567^(@)C , then the rate of energy radiation becomes

The energy emitted per second by a black body at 27^(@)C is 10 J. If the temperature of the black body is increased to 327^(@)C , the energy emitted per second will be

The temperature of a body is increased from –73°C to 327°C. Then the ratio of emissive power is –

The energy emitted per second by a black body at 1227^(@)C is E. If the temperature of the black body is increased to 2727^(@)C the energy emitted per second in the terms of E in the second case.

If the temperature of a black body be increased from 27^(@)C to 327^(@)C the radiation emitted increases by a fraction of

The temperature of a body in increased from 27^(@)C to 127^(@)C . By what factor would the radiation emitted by it increase?