[" If "a,b,c" are in A."P" .show that "],[ |[x+1,x+2,x+a],[x+2,x+3,x+b],[x+3,x+4,x+c]|=0]

If a,b,c are in AP show that |[x+1,x+2,x+a],[x+2,x+3,x+b],[x+3,x+4,x+c]|=0

If a,b,c are in AP show that |[x+1,x+2,x+a],[x+2,x+3,x+b],[x+3,x+4,x+c]|=0

if a, b,c are in A.P. then what is the value of: |[x+1,x+2,x+a],[x+2,x+3,x+b],[x+3,x+4,x+c]| ?

If a,b,c, are in A.P. then |(x+1,x+2,x+a),(x+2,x+3,x+b),(x+3,x+4,x+c)|=

If a,b,c are in A.P., then the determinant |[x+2, x+3, x+2a],[x+3,x+4,x+2b],[x+4,x+5,x+2c]| is

If a, b, c, are in A.P, then the determinant |[x+2,x+3,x+2a],[x+3,x+4,x+2b],[x+4,x+5,x+2c]| is:

Given a,b,c are in A.P. Then determinant : |(x+1,x+2,x+a),(x+2,x+3,x+b),(x+3,x+4,x+c)| in its simplified form is :

If a, b, c, are in A.P, then the determinant |[x+2,x+3,x+2a], [x+3,x+4,x+2b], [x+4,x+5,x+2c]| is(A) 0 (B) 1 (C) x (D) 2x

If a,b,c are A.P then |{:(x+1,x+2,x+a),(x+2,x+3,x+b),(x+3,x+4,x+c):}|=0

Choose the correct answer in questions 17 to 19: If a, b, c are in A.P., then the determinant [{:(x+2,x+3,x+2a),(x+3,x+4,x+3b),(x+4,x+5,x+2c):}] is : (a) 0 (b) 1 ( c) x (d) 2x