Home
Class 12
PHYSICS
[" 15.Displacement time equation of a pa...

[" 15.Displacement time equation of a particle "],[" executing SHM is "x=a sin(wt+pi/6)" .Time "],[" taken by the particle to go directly from "],[x=-A/2" to "x=+A/2" is "],[[" 1) "(pi)/(3w)," 2) "(pi)/(2w)],[" 3) "(2 pi)/(w)," 4) "(pi)/(w)]]

Promotional Banner

Similar Questions

Explore conceptually related problems

Displacement-time equation of a particle executing SHM is x=A sin (omega t+(pi)/6) Time taken by the particle to go directly from x=-A/2"to"x=+A/2

Displacement-time equation of a particle execution SHM is x=A sin( omegat+pi/6) Time taken by the particle to go directly from x = -A/2 to x = + A/2 is

Displacement-time equation of a particle execution SHM is x=A sin( omegat+pi/6) Time taken by the particle to go directly from x = -A/2 to x = + A/2 is

Displacement time equation of a particle executing SHM is, x = 10 sin ((pi)/(3)t+(pi)/(6))cm . The distance covered by particle in 3s is