(1)/(x+1)-(1)/(x)<=(1)/(x-1)-(1)/(x-2)

If y=(1+(1)/(x))^(x), then (dy)/(dx)=(1+(1)/(x))^(x){log(1+(1)/(x))-(1)/(x+1)}(b)(1+(1)/(x))^(x)log(1+(1)/(x))(c)(x+(1)/(x))^(x){log(x+1)-(x)/(x+1)}(d)(x+(1)/(x))^(x){log(1+(1)/(x))+(1)/(x+1)}

Solve by factorization: (x+1)/(x-1)-(x-1)/(x+1)=5/6,\ \ x!=1,\ -1

Solve by factorization: (x+1)/(x-1)-(x-1)/(x+1)=(5)/(6),x!=1,-1

For x>0 the sum of the series (1)/(1+x)-(1-x)/((1+x)^(2))+((1-x)^(2))/((1+x)^(3))-...oo is equal to

If y=x+(1)/(x+(1)/(x+(1)/(x+(1)/(x+...)))), prove that (dy)/(dx)=(1)/(2(x)/(x+(1)/(x+(1)/(x+1))))

If x ne pm 1 , then (x+1)/(x-1)-(x-1)/(x+1)=

What is (8x)/(1-x^(4)) - (4x)/(x^(2) +1) +(x+1)/(x-1) - (x-1)/(x+1) equal to?

f (x)= (1)/(1+ (1)/(x))g (x) =(1)/(1 + (1)/(f(x)))implies g'(2)=