cos theta+cos^(2)theta=1,a sin^(12)theta+b sin^(10)theta+c sin^(3)theta

cos theta+cos^(2)theta=1,a sin^(12)theta+b sin^(10)theta+c sin^(8)theta+d sin^(6)theta=1rArr(b+c)/(a+d)=

If cos theta+cos^(2)theta=1, prove that sin^(12)theta+3sin^(10)theta+3sin^(8)theta+sin^(6)theta+2sin^(4)theta+2sin^(2)theta-2=1

If Sin theta+ Sin^(2) theta=1 and cos a cos^(12) theta+ b cos ^(12) theta+ b cos^(10) theta+ c cos^(8) theta+d cos^(6)-1 theta = then (b+c)/(a+d)

If cos theta+ cos^2 theta=1 , prove that sin^12 theta+3sin^10 theta+3sin^8theta+sin^6theta+2sin^4theta+2sin^2theta-2=1

If sin theta+sin ^(2) theta=1 then cos ^(12) theta+3 cos ^(10) theta+3 cos ^(8) theta+cos ^(6) theta=

If f(theta)=|(cos^(2) theta, cos theta sin theta, -sin theta),(cos theta sin theta, sin^(2) theta, cos theta),(sin theta, -cos theta, 0)| then f((pi)/12)=

Evaluate the following determinants: (b) |(cos theta, -sin theta),(sin theta, cos theta)| = cos theta (cos theta) - sin theta(-sin theta) = cos^(2) theta + sin^(2) theta = 1

4 sin theta * cos^(3) theta-4 cos theta * sin ^(3)theta= A) 4 cos theta B) cos 4 theta C) 4 sin theta D) sin 4 theta

If f (theta) = [[cos^(2) theta , cos theta sin theta,-sin theta],[cos theta sin theta , sin^(2) theta , cos theta ],[sin theta ,-cos theta , 0]] ,then f ( pi / 7) is