" II "(6x+1)/(3)+1=(x-3)/(6)

Solve (6x+1)/(3)+1=(x-3)/(6)

Solve (6x+1)/3+1=(x-3)/6

Solve : (6x+1)/(2)+1=(7x-3)/(3)

Solve (6x+1)/3 + 1=(x-3)/6

If (6x+1)/3 + 1 = (x-3)/6 , then x = ?

If d/(dx) {f(x)}=1/(1+x^2) then d/(dx){f(x^3)} is a) (3x)/(1+x^3) b) (3x^2)/(1+x^6) c) (-6x^5)/(1+x^6)^2 d) (-6x^5)/(1+x^6)

int(x+x^(2/3)+2x^(1/6))/(x(1+x^(1/3)))dx=A*x^(2/3)+B tan^(-1)(x^(1/6))+c, then (i) A=(3)/(2),( ii) B=12, (iii) A=(2)/(3), (iv) B=(1)/(6)

int_(, then f(x))^( If )(dx)/(x^(3)(1+x^(6))^(2/3))=x*f(x)*(1+x^(6))^(1/3)+C