`f and g` are functions defined from `R->R` If `f(x-2)=x^2 and g(x)=(x+2)^2` then `f(x)+g(x-2)=?`

If f: R->R and g: R->R be functions defined by f(x)=x^2+1 and g(x)=sinx , then find fog and gof .

If f: R->R and g: R->R be functions defined by f(x)=x^2+1 and g(x)=sinx , then find fog and gof .

Let f: R->R , g: R->R be two functions defined by f(x)=x^2+x+1 and g(x)=1-x^2 . Write fog\ (-2) .

Let f: R->R , g: R->R be two functions defined by f(x)=x^2+x+1 and g(x)=1-x^2 . Write fog\ (-2) .

If f: R to R, g : R to R functions defined by f(x) = 3x-2, g(x) =x^(2)+1 , then (gof^(-1)) (2)=

If f: R to R and g: R to R be two functions defined as f(x)=x^(2) and g(x)=5x where x in R , then prove that (fog)(2) ne (gof) (2).

If f: R to R and g: R to R be two functions defined as f(x)=x^(2) and g(x)=5x where x in R , then prove that (fog)(2) ne (gof) (2).

If f:R→R and g:R→R be two functions defined as below, then find fog(x) and gof(x); f(x)=2x+3,g(x)=x^2+5

IF f:R to R,g:R to R are defined by f(x)=3x-1 and g(x)=x^2+1 , then find (fog)(2)