If M=mass of wire, `rho`=density of wire, R=radius of wire, r=change in radius, L=original length of wire and l=change in length, then poisson's ratio is given by

There is no change in the volume of a wire due to the change in its length on stretching. The Poisson's ratio of the material of the wire is

If there is no change in the volume of a wire due to change in it's length on stretching , what would be the poisson's ratio of the material.

A wire of length L and radius r is clamped at one end. If its other end is pulled by a force F, its length increases by l . If the radius of the wire and the applied force both are reduced to half of their original values keeping original length constant. Find the ratio of the change in length of first wire versus second wire?

A force F is applied on the wire of radius r and length L and change in the length of wire is l . If the same force F is applied on the wire of the same material and radius 2r and length 2L. Then the change in length of the other wire is

A wire of length L radius r when stretched with a force F changes in length by l. What will be the change in the length of a wire of same material having length 2 L radius 2 r and stretched by a force 2 F ?

A wire of length L and radius r when stretched with a force F changes in length by l. What will be the change in length of a wire of same material having length 2L, radius 2r and stretched by a force 2F?