(1+x)(dy)/(dx)=((1+x)^(2)+(y-3))," If "y(2)=0" then "y(3)=?

(y-x(dy)/(dx))=3(1-x^(2)(dy)/(dx))

(dy)/(dx)=(x+y+1)/(2x+2y+3)

(dy)/(dx)=(x+y+1)/(2x+2y+3)

(dy)/(dx)+(1)/(2x)y=(x)/(y^(3))

Solve : (dy)/(dx)= (1)/(1+x^(2)), y(0)=3 .

If (dy)/(dx)=(2^(x+y)-2^(x))/(2^(y)),y(0)=1 then y(1) is equal to

(1+x+xy^(2))(dy)/(dx)+(y+y^(3))=0

Solve the following differential equations (i) (1+y^(2))dx = (tan^(-1)y - x)dy (ii) (x+2y^(3))(dy)/(dx) = y (x-(1)/(y))(dy)/(dx) + y^(2) = 0 (iv) (dy)/(dx)(x^(2)y^(3)+xy) = 1