[" To a "10mL" of "10^(-3)NH_(2)SO_(4)" solution "],[" water has been added to make the "],[" total volume to one litre.Its pOH "],[" would be :- "]

To a 10mL of 10^(-3) N H_(2)SO_(4) solution water has been to make the total volume of one litre. Its pOH would be :

To a 10mL of 10^(-3) N H_(2)SO_(4) solution water has been to make the total volume of one litre. Its pOH would be :

To a 10mL of 10^(-3) N H_(2)SO_(4) solution water has been to make the total volume of one litre. Its pOH would be :

22.7 mL of (N/10) Na_(2)CO_(3) solution neutralises 10.2 mL of a dilute H_(2)SO_(4) solution. The volume of water that must be added to 400 mL of this H_(2)SO_(4) solution in order to make it exactly N/10.

22.7 mL of (N/10) Na_(2)CO_(3) solution neutralises 10.2 mL of a dilute H_(2)SO_(4) solution. The volume of water that must be added to 400 mL of this H_(2)SO_(4) solution in order to make it exactly N/10.

10ml of N-HCl 20ml of N//2 H_(2)SO_(4) and 30 ml of N//3 HNO_(3) are mixed together and volume made to one litre. The normality of the resulting solution is -

5mL of N HCI, 20 mL of N//2 H_(2)SO_(4) and 30 mL of N//3 HNO_(3) are mixed together and volume made to one litre. The normality of the resulting solution is