In order to make the effective acceleration due to gravity at the equator to zero, the numerical value of the angular velocity of rotation of the earth should be
[Radius of the earth=6400 km, `g=10m/s^(2)`]

The acceleration due to gravity at the latitude 45^(@) on the earth becomes zero if the angular velocity of rotation of the earth is

What is the difference in the values of acceleration due to gravity at the polar region and at the equator due to the diurnal motion of the earth ? Radius of the earth=6400 km.

The numerical value of the angular velocity of rotation of the earth should be…….. Rad/s in order to make the effective acceleration due to gravity equal to zero.

The numerical value of the angular velocity of rotation of the earth should be…….. Rad/s in order to make the effective acceleration due to gravity equal to zero.

Calculate that imaginary angular velocity of the Earth for which effective acceleration due to gravity at the equator becomes zero. In this condition, find the length (in hours) of a day? Radius of Earth = 6400 km. g = 10 ms^(-2) .