A parallel plate condenser is filled with two dielectrics as shown. Area of each plate is `A "metre"^(2)` and the separtion is `t` metre. The dielectric constants are `K_(1)` and `K_(2)`, respectively. Its capacitance in farad will be

A parallel plate capacitor is filled with dielectrics as shown in Fig. What is its capacitance ?

A parallel plate capacitor of plate area A and separation d filled with three dielectric materials as show in figure. The dielectric constants are K_1 , K_2 and K_3 respectively. The capacitance across AB will be :

A capacitor of plate area A and separation d is filled with two dielectrics of dielectric constant K_(1) = 6 and K_(2) = 4 . New capacitance will be

The capacitance of a parallel plate capacitor with plate area A and separation d is C . The space between the plates in filled with two wedges of dielectric constants K_(1) and K_(2) respectively. Find the capacitance of resulting capacitor.

The capacitance of a parallel plate capacitor with plate area A and separation d is C . The space between the plates in filled with two wedges of dielectric constants K_(1) and K_(2) respectively. Find the capacitance of resulting capacitor.