How many moles of sucrose should be dissolved in 500 g of water so as to get a solution which has a difference of `103.57^(@)C` between boiling point and freezing point :-
`(K_(f)=1.86" K kg mol"^(-1), K_(b)="0.52 K kg mol"^(-1))`

How many moles of sucrose should be dissolved in 500 g of water so as to get a solution which has a difference of 104^(@)C between boiling point and freezing point ? ( K_(f) = 1.86 K kg mol^(-1) , K_(b) = 0.52 K kg mol^(-1) )

How many moles of sucrose should be dissolved in 500gms of water so as to get a solution which has a difference of 104^(@)C between boiling point and freezing point. (K_(f)=1.86 K Kg "mol"^(-1).K_(b)=0.52K Kg "mol"^(-1))

How many grams of sucrose (molecular weight 342) should be dissolved in 100 g water in order to produce a solution with 105^(@)C difference between the freezing point and the boiling point ? (K_(b) =0.51^(@)C m^(-1) , (K_(f) =1.86^(@)C m^(-1))

How many grams of sucrose (molecular weight 342) should be dissolved in 100 g water in order to produce a solution with 105^(@)C difference between the freezing point and the boiling point ? (K_(b) =0.51^(@)C m^(-1) , (K_(f) =1.86^(@)C m^(-1))

How many grams of sucrose (molecular weight 342) should be dissolved in 100 g water in order to produce a solution with 105^(@)C difference between the freezing point and the boiling point ? (K_(b) =0.51^(@)C m^(-1) , (K_(f) =1.86^(@)C m^(-1))