The boiling point of water `(100^(@)C)`becomes `100.25^(@)C`if `3`gramss of a nonvolatile solute is dissolved in `200 ml`of water.The molecular weight of solute is

The boiling point fo water (100^(@)C become 100.52^(@)C , if 3 grams of a nonvolatile solute is dissolved in 200 ml of water. The molecular weight of solute is ( K_(b) for water is 0.6 "K.kg mol"^(-1) )

The boiling point of water (100^(@) C) becomes 100.52 ^(@) C if 3 grams of non-volatile solute is dissolved in 200 mL of water . The molecular weight of solute is ______ (K_(b) "for water is " 0.6K kg mol ^(-1))

The boiling point of water (100^(@)C) becomes 100.52^(@) C if 3 g of a non - volatile solute is dissolved in 20 ml of it . Calculate the molar mass of the solute ( k_(b) for water = 0.52 K m^(-1) ).

The molal boiling point constant for water is 0.513^(@)C kgmol^(-1) . When 0.1 mole of sugar is dissolved in 200 ml of water , the solution boils under a pressure of one atmosphere at

The molal boiling point constant for water is 0.513^(@)C kgmol^(-1) . When 0.1 mole of sugar is dissolved in 200 ml of water , the solution boils under a pressure of one atmosphere at

The molal boiling point constant for water is 0.513^(@)C kgmol^(-1) . When 0.1 mole of sugar is dissolved in 200 ml of water , the solution boils under a pressure of one atmosphere at