`A(s)hArr2B(g)+C(g)`
The above equilibrium was established by initially taking `A(s)` only. At equilibrium, `B` is removed so that its partial pressure at new equilibrium becomes `1//3^(rd)` of original total preswsure. Ratio of total pressure at new equilibrium and at initial equilibrium will be :

Solid Ammonium carbamate dissociates as: NH_(2)COONH_(4)(s)hArr2NH_(3)(g)+CO_(2)(g). In a closed vessel, solid ammonium carbonate is in equilibrium with its dissociation products. At equilibrium, ammonia is added such that the partial pressure of NH_(3) at new equilibrium now equals the original total pressure. Calculate the ratio of total pressure at new equilibrium to that of original total pressure. Also find the partial pressure of ammonia gas added.

Solid Ammonium carbamate dissociates as: NH_(2)COONH_(4)(s)hArr2NH_(3)(g)+CO_(2)(g). In a closed vessel, solid ammonium carbonate is in equilibrium with its dissociation products. At equilibrium, ammonia is added such that the partial pressure of NH_(3) at new equilibrium now equals the original total pressure. Calculate the ratio of total pressure at new equilibrium to that of original total pressure. Also find the partial pressure of ammonia gas added.

Solid Ammonium carbamate dissociates as: NH_(2)COONH_(4)(s)hArr2NH_(3)(g)+CO_(2)(g). In a closed vessel, solid ammonium carbamate is in equilibrium with its dissociation products. At equilibrium, ammonia is added such that the partial pressure of NH_(3) at new equilibrium now equals the original total pressure. Calculate the ratio of total pressure at new equilibrium to that of original total pressure.

C(s)+CO_(2)(g) iff 2CO(g) . At equilibrium, 25% of the CO_(2) got converted into CO. If the equilibrium pressure is 12 atm, the partial pressure of CO_(2) at equilibrium is

For the reaction AB(g)hArrA(g)+B(g) , at equilibrium AB is 20% dissociated at a total pressure of P, The equilibrium constant K_(p) is related to tha total pressure by the expression

K_(p) for the reaction A hArr B is 4. If initially only A is present then what will be the partial pressure of B after equilibrium ?

K_(p) for the reaction A hArr B is 4. If initially only A is present then what will be the partial pressure of B after equilibrium ?

A solid A dissociates to give B and C gases as shown, A(s) hArr 2B(g)+3C(g) At equilibrium some B(g) is introduced keeping volume constant so that pressure of B of new equilibrium becomes equal to 8/(5sqrt2) times original total pressure calculate ratio of initial equilibrium pressure of C to that of its final pressure