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The nucleus of an atom of .(92)Y^(235) i...

The nucleus of an atom of `._(92)Y^(235)` initially at rest decays by emitting an `alpha` particle. The binding energy per nucleon of parent and dougther nuclei are 7.8MeV and 7.835MeV respectively and that of `alpha` particles is `7.07MeV//"nucleon"`. Assuming the dougther nucleus to be formed in the unexcited state and neglecting its share of energy in the reaction, calculate speed of emitted alpha particle. Take mass of `alpha` particle to be `6.68xx10^(-27)kg`.

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The nucleus of an atom of ._(92)Y^(235) initially at rest decays by emitting an alpha particle. The binding energy per nucleon of parent and daughter nuclei are 7.8MeV and 7.835MeV respectively and that of alpha particles is 7.07MeV//"nucleon" . Assuming the daughter nucleus to be formed in the unexcited state and neglecting its share of energy in the reaction, calculate speed of emitted alpha particle. Take mass of alpha particle to be 6.68xx10^(-27)kg .

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