[" A real valued function "f(x)" satisfies the functional equation "],[qquad f(x-y)=f(x)f(y)-f(a-x)f(a+y)]

A real valued function f(x) satisfies the functional equation : f(x-y)=f(x)f(y)-f(a-x)f(a+y) , where a is given constant and f(0)=1.f(2a-x) is equal to :

A real valued function f (x) satisfies the functional equation f (x-y)= f(x) f(y) - f(a-x) f(a +y) where a is a given constant and f (0) =1, f(2a -x) is equal to

A real valued function f(x) satisfies the functional equation f(x-y) = f(x)f(y)-f(a - x)f(a + y) where a is a given constant and f(0)=1, f(2a-x) is equal to:

A real valued function f(x) satisfies the functional equation f(x-y)=f(x)f(y)-f(a-x)f(a+y) where a is a given constant and f(0), f (2a-x)=

A real valued function f(x) satisfies the functional equation f(x-y) = f(x) f(y) - f(a-x) f(a+y) , where a is a given constant and f(0)=1 , f(2a-x) =?

A real valued function f(x) satisfies the functional equation f(x-y) = f(x) f(y) - f(a-x) f(a+y) , where a is a given constant and f(0)=1 , f(2a-x) =?

A real valued function f (x) satisfies the functional equation f (x-y)=f(x)f(y)- f(a-x) f(a+y) where 'a' is a given constant and f (0) =1, f(2a-x) is equal to :

A real-valued function f(x) satisfies the functional equation f(x-y)=f(x)f(y)-f(a-x)f(a+y), where a is a given constant and f(0)=1. Then prove that f(x) is symmetrical about point (a, 0).

A real-valued functin f(x) satisfies the functional equation f(x-y)=f(x)f(y)-f(a-x)f(a+y), where a given constant and f(0)=1. Then prove that f(x) is symmetrical about point (a, 0).