If `x=a e^t(sint+cost)` and `y=a e^t(sint-cost),` prove that `(dy)/(dx)=(x+y)/(x-y)dot`

Explanation

To prove that \(\frac{dy}{dx} = \frac{x+y}{x-y}\), we start with the given equations:

\[ x = a e^t (\sin t + \cos t) \]
\[ y = a e^t (\sin t - \cos t) \]
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