A capacitor is filled with two dielectrics of same dimensions, but of dielectric constants 2 and 3 respectively. Find the ratio of capacitances in the two arrangements shown in Fig.

The capacitance of a capacitor, filled with two dielectrics of same dimensions but of dielectric constants K_1 and K_2 respectively as shown will be -

The space between parallel plate capacitors is filled with four dielectrics of equal dimensions but of dielectric constants K_(1), K_(2), K_(3)andK_(4) respectively. If K is the dielectric constant of a single dielectric that must be filled between capacitor plates to have the same capacitance between A and B. Then we must have

Two identical parallel plate capacitors, of capacitance C each, have plates of area A, separated by a distance d. The space between the plates of the two capacitors, is filled with three dielectrics, of equal thickness and dielectric constants K_(1), K_(2) and K_(3) . The first capacitor is filled as shown in fig. I, and the second one is filled as shown in fig. II. If these two modified capacitors are charged by the same potential V, the ratio of the energy stored in the two, would be ( E_(1) refers to capacitor (I) and E_(2) to capacitor (II)):

Two identical parallel plate capacitors, of capacitance C each, have plates of area A, separated by a distance d. The space between the plates of the two capacitors, is filled with three dielectrics, of equal thickness and dielectric constants K_(1),K_(2) and K_(3) . The first capacitor is filled as shown in fig. I, and the second one is filled as shown in fig. II. If these two modified capacitors are charged by the same potential V, the ratio of the energy stored in the two, would be ( E_(1) refers to capacitor (I) and E_(2) to capacitor (II)):

Capacitor has square plates of side l .Three dielectrics fill the space as shown (their dielectric constants are given).Find equivalent capacitance.