Given that `sqrt5=2.236` apporximately; find the three places of decimal the value of `3/sqrt5`

Given that sqrt(5)=2.236 approximately,find the three places of decimals the value of (2)/(sqrt(5))

Given that sqrt(5)=2.236 approximately,find to three places of decimals the value of (2)/(sqrt(5)) .

If sqrt(3)=1.7321 then find correct to three places of decimals,the value of (1)/(2sqrt(48)+sqrt(192)-sqrt(75))

Find the value of sqrt(3) upto three places of decimal.

It being given that sqrt(2) = 1.414, sqrt(3) = 1.732, sqrt(5) = 2.236 and sqrt(10)= 3.162 , find the value to three places of decimials, of each of the following . (i) (2)/(sqrt(5)) (ii) (2- sqrt(3))/(sqrt(3)) (iii) (sqrt(10) - sqrt(5))/(sqrt(2))

If sqrt(15)= 3.87 find the value of sqrt3/sqrt5

Given sqrt(2)=1.414, sqrt(3)=1.732, sqrt(5)=2.236 , find the value, correct to three decimals of the following (1-sqrt(3))/(sqrt(5)-sqrt(2))