If `a+b+c=6` and `ab+bc+ca=11` is given then find the value of `a^3+b^3+c^3-3abc`

(i) If a^(2)+b^(2)+c^(2)=20 " and" a+b+c=0, " find " ab+bc+ac . (ii) If a^(2)+b^(2)+c^(2)=250 " and" ab+bc+ca=3, " find" a+b+c . (iii) If a+b+c=11 and ab+bc+ca=25, then find the value of a^(3)+b^(3)+c^(3)-3 abc.

If a+b+c=6 and ab+bc+ca=11 find the value of a^(3)+b^(3)+c^(3)-3abc

If a+b+c=6 and ab+bc+ca=11, find the value of a^(3)+b^(3)+c^(3)-3abc.

If a + b + c = 9 and ab + bc + ca = 18, then the value of a^(3)+b^(3)+c^(3) + 3abc is :

If a+b+c = 4 and ab + bc + ca = 1, then the value of a^3+b^3+c^3-3abc is: यदि a+b+c = 4 और ab + bc + ca = 1 है, तो a^3+b^3+c^3-3abc का मान क्या होगा ?

If a +b + c = 19, ab + bc + ca = 120 then what is the value of a^3 + b^3 + c^3 - 3abc?