A triangle ABC is right angled at A. AL is drawn perpendicular to BC. Prove that ` /_BAL = /_ACB`

A triangle ABC is right angles at Adot AL is drawn perpendicular to BC. Prove that /_BAL=/_ACB

In a right triangle ABC, right angled at A, AD is drawn perpendicular to BC. Prove that: AB^(2)-BD^(2)= AC^(2)-CD^(2)

A Delta ABC is right angled at A. L is a point on BC such that AL bot BC. Prove that /_BAL = /_ACB .

In right angled triangle ABC,/_A is right angle.AD is perpendicular to the hypotenuse BC.Prove that (Delta ABC)/(Delta ACD)=(BC^(2))/(AC^(2))

ABC is a right-angled triangled, right angled at A*AD is drawn perpendicular to BC from A . Then AB^2 is equal to

ABC is a right angled triangle of which A is the right angle, BD is drawn perpendicular to BC meets CA produced in D. If AB = 12, AC = 16, BC = 20, then BD =

In the figure given below , ABC is right angled at B and Delta ABD is right angled at A. If BD is perpendicular to AC and BC=2sqrt3 cm with angle CAB=30^(@) , then the length of AD is___

ABC is a triangle right angled at A and AD is perpendicular to BC. If BD = 8 cm and DC =12.5 cm, then what is AD equal to ?