The sides BC;CA and AB of a `Delta ABC`; are produced in order; forming exterior angles `/_ACD;/_BAE and /_CBF`. Show that `/_ACD + /_BAE + /_CBF = 360^@`

The sides BC,CA and AB of a triangle ABC, are produced in order,forming exterior angles /_ACD,/_BAE and /_CBF. Show that /_ACD+/_BAE+/_CBF=360^(@)

The sides BC,CA and AB of a ABC, are produced in order,forming exterior angles /_ACD,/_BAE and /_CBF .Show that /_ACD+/_BAE+/_CBF=360^(@)

The sides BC,CA and AB of triangle ABC have been produced to D, E and F respectively as shown in the figure, forming exterior angles angle ACD, angle BAE and angle CBF . Then, angle ACD + angle BAE + angle CBF is equal to

If the sides of a triangle are produced in an order, show that the sum of the exterior angles so formed is 360°.

In the above figure ( not to scale ) the sides BA,BC and CA of Delta ABC are produced to D,F, and E respectively such that /_ ACF= 120^(@) and /_ BAE= 150^(@) . Then /_ ABC = ________ .

The side BC of a ABC is produced on both sides.Show that the sum of the exterior angles so formed is greater than /_A by two right angles.

The side BC of a ABC is produced on both sides.Show that the sum of the exterior angles so formed is greater than /_A by two right angles.

In Figure,the sides BC,CA and AB of a ABC have been produced to D,E and F respectively.If /_ACD=105^(@) and /_EAF=45^(@), find all the angles of the ABC

The side BC of a ABC is produced,such that D is one ray BC. The bisector of /_A meets BC in L as shown in Figure.Prove that /_ABC+/_ACD=2/_ALC