In a S.H.M. with amplitude 'A', what is the ratio of K.E. and P.E. at `(A)/(2)` distance from the mean position ?

The particle performing S.H.M. along a straight line about the mean position with an amplitude 'A'. Then the maximum potential energy at a distance A from the extreme position is

If particle executing S.H.M. has an amplitude of 6 cm, its acceleration at a distance 2 cm from mean position is 8 cm/s^2 , then the maximum speed of the particle will be

At what distance from mean position is K.E equal to P.E?

A particle executes a linear S.H.M. of amplitude A. At what dis"tan"ce from the mean position is its K.E. equal to its P.E. ?

A particle executes SHM on a line 8 cm long. Its K.E. and P.E. will be equal when its distance from the mean position is :-

A particle executes SHM on a line 8 cm long. Its K.E. and P.E. will be equal when its distance from the mean position is :-