`/_\ABC` is an obtuse triangle; obtuse-angled at B. If `AD_|_CB` ; prove that `(AC)^2 = (AB)^2 +(BC)^2 + 2 BC . BD`

In the given figure, Delta ABC is an obtuse triangle, obtuse-angled at B. If AD bot CB (produced ) prot that AC^(2)=AB^(2)+BC^(2)+2BC*BD

(Result on obtuse triangle) In Fig.4.183,ABC is an obtuse triangle,obtuse angled at B. If AD perp CB ,prove that AC^(2)=AB^(2)+BC^(2)+2BC xx BD (FIGURE)

In fig. /_B of /_\ABC is an acute angle and AD _|_ BC ; prove that AC^2 = AB^2 + BC^2 - 2 BC xx BD

Delta ABD is a right triangle,right-angled at A and AC perp BD. Prove that AB^(2)=BC xx BD

In a Delta ABC , angleB is an acute-angle and AD bot BC Prove that : (i) AC^(2) = AB^(2) + BC^(2) - 2 BC xx BD (ii) AB^(2) + CD^(2) = AC^(2) + BD^(2)

ABC is a right triangle with AB = AC.If bisector of angle A meet BC at D then prove that BC =2 AD .

(Result on acute triangle) In Fig.4.184,/_B of ABC is an acute angle and AD perp BC, prove that AC^(2)=AB^(2)+BC^(2)-2BC xx BD

ABC is an isosceles triangle with AC = BC. If AB^2 - 2AC^2 =0, prove that ABC is right triangle.

In a right-angled triangle,the square of hypotenuse is equal to the sum of the squares of the two sides.Given that /_B of /_ABC is an acute angle and AD perp BC .Prove that AC^(2)=AB^(2)+BC^(2)-2BC.BD

In a Delta ABC, /_ B is an acute-angle and AD bot BC . Prove that: AB^2 + CD^2 = AC^2 + BD^2