In fig. `/_B` of `/_\ABC` is an acute angle and `AD _|_ BC` ; prove that `AC^2 = AB^2 + BC^2 - 2 BC xx BD`

(Result on acute triangle) In Fig.4.184,/_B of ABC is an acute angle and AD perp BC, prove that AC^(2)=AB^(2)+BC^(2)-2BC xx BD

In a right-angled triangle,the square of hypotenuse is equal to the sum of the squares of the two sides.Given that /_B of /_ABC is an acute angle and AD perp BC .Prove that AC^(2)=AB^(2)+BC^(2)-2BC.BD

In a Delta ABC , angleB is an acute-angle and AD bot BC Prove that : (i) AC^(2) = AB^(2) + BC^(2) - 2 BC xx BD (ii) AB^(2) + CD^(2) = AC^(2) + BD^(2)

In a Delta ABC, /_ B is an acute-angle and AD bot BC . Prove that: AB^2 + CD^2 = AC^2 + BD^2

In figure,/_B<90^(@) and AD perp BC .Prove that AC^(2)=AB^(2)+BC^(2)-2BC.BD

In an equilateral ABC,AD perp BC, prove that AD^(2)=3BD^(2)

(Result on obtuse triangle) In Fig.4.183,ABC is an obtuse triangle,obtuse angled at B. If AD perp CB ,prove that AC^(2)=AB^(2)+BC^(2)+2BC xx BD (FIGURE)

In the figure , ABC is triangle in which angleABClt90^(@)andADbotBC . Prove that AC^(2)=AB^(2)+BC^(2)-2BC*BD .

In the figure given below ABC is a triangle right angled at A and AC bot BD . Show that AB^(2) = BC xx BD

In the given figure if AD bot BC prove that AB^(2)+CD^(2)= BD^(2) +AC^(2)