In what ratio should you mix `0.2 M NaNO_(3)` and `0.1 M Ca (NO_(3))_(2)` solution so that in resulting solution the concentration of -ve ion is 50 % greater than the concentration of + ve ions?

What volumes should you mix of 0.2 M NaCl and 0.1 M CaCl_(2) solution so that in resulting solution the concentration of positive ion is 40% lesser than concentration of negative ion. Assuming total volume of solution 1000 ml.

Equal volumes of 0.1 MAgNO_(3) and 0.1 M NaCl solutions are mixed. The concentration of NO_(3)^(-) in the mixed solution is

Equal volumes of 0.1 M AgNO_(3) and 0.2 M NaCl solutions are mixed. The concentration of nitrate ions in the resultant mixture will be

20 ml of CaCl_(2) solution is mixed with 30 ml of 0.1MAlCl_(3) solution. If the resulting solution has chloride ion concentration equal is 0.34 M, the concentration of CaCl_(2) solution added is :

The concentration of OH^(-) ions in a 0.050 M HNO_(3) solution is

The hydrogen ion concentration of 0.001 M NaOH solution is

The hydrogen ion concentration of a solution is 0.01 M, What is P^(H) ?