`(tanA + cosecB)^2 - (Cot B - Sec A)^2 = 2 tana cot B( Cosec A + Sec B)`

Prove (tan A + cos ecB) ^ (2) - (cot B-sec A) ^ (2) = 2tan A cot B (cos ecA + sec B)

Prove the following identities: (1+tan A tan B)^(2)+(tan A-tan B)^(2)=sec^(2)A sec^(2)B(tan A+csc B)^(2)-(cot B-sec A)^(2)=2tan A cot B(csc A+sec B)

(tan A+cot A)=(sec A*csc A)

tan B+cot B=2sec2A rArr A+B=

(1+tan A+sec A)(1+cot A-cosec A)=

The value of (tan^2 A+cot^2 A-2)- sec^2 A cosec^2 A is: (tan^2 A+cot^2 A-2)- sec^2 A cosec^2 A का मान क्या होगा ?

(6) 1+tanA tan2A = sec2A

If A and B are complementary angles, then the value of sin A cos B + cos A sin B - tanA tan B + sec^(2) A - cot^2 B is