A circle is touching the side BC of `DeltaABC` at P and touching AB and AC produced at Q and R respectively Prove that `AQ=1/2`(Perimeter of `DeltaABC`)

A circle is touching the side BC of ABC at P and touching AB and AC produced at Q and R respectively.Prove that AQ=(1)/(2)(Perimeter of ABC)

A circle touches the side BC of DeltaABC at P and touches AB and AC produced at Q and R respectively. Prove that AQ=1/2(Perimeter of DeltaABC).

A circle touches the side BC of a Delta ABC at P and also touches AB and AC produced at Q and R, respectively. If the perimeter of Delta ABC = 26.4 cm, then the length of AQ is:

A circle touches the side BC of Delta ABC at F and touches AB and AC at D and E, respectively. If AD = 8 cm, then find the perimeter of Delta ABC .

A circle touches the side BC of DeltaABC at D and AB and aC are produced to E and F, respectively. If AB=10cm, AC=8.6 cm and BC=6.4 cm then BE=?

25.In figure,the sides AB,BC and CA of triangle ABC touch a circle with centre and radius r at P,Q and R respectively.Prove that (i) AB+CQ=AC+BQ (ii) Area Delta ABC=(1)/(2) perimeter of Delta ABC).r

A circle with centre P is inscribed in the Delta ABC Side AB, side BC and side A C touch the circle at points L,M and N respectively . Prove that : A (DeltaABC ) = 1/2 (AB +BC + AC) xxr

A circle is inscribed in a DeltaABC touching AB, BC and AC at P, Q and R respectively. If AB = 10 cm, AR = 7 cm and CR = 5 cm, then find the length of BC.