The elevation of a tower at a Station A due north of it is `alpha` and at a station B due west of A is `beta`. Prove that the height of the tower is `(ABsinalphasinbeta)/sqrt(sin^alpha-sin^beta)`

The elevation of a tower at a station A due north of it is alpha and at a station B due west of A is beta. Prove that the height of the tower is (AB sin alpha sin beta)/(sqrt(sin^(2)alpha-sin^(2)beta))

The elevation of a tower at a station A due North of it is alpha and at a station B due West of A is beta .Prove that height of the tower is (AB sin alpha sin beta)/(sin^(2)alpha-sin^(2)beta)

The angle of elevation of a tower PQ at a point A due north of it is 30^(@) and at another point B due east of A is 18^(@) . If AB =a. Then the height of the tower is

The angular elevation of a tower OP at a point A due south of it is 60^@ and at a point B due west of A, the elevation is 30^@ . If AB=3m, the height of the tower is

The angle of elevation of the top of a tower at a point A due south of the tower is alpha and at beta due east of the tower is beta . If AB=d, then height of the tower is

The angle of elevation of the top of a tower from a point A due south of the tower is alpha and from B due east of tower is beta. If AB=d , show that the height of the tower is (d)/(sqrt(cot^(2)alpha+cot^(2)beta))