Combination of quadrilateral and circle : In Figure; ABCD is a trapezium with AB||DC and `/_BCD = 60^@`. IF BFEC is a sector of a circle with centre C and AB = BC = 7cm and DE = 4cm. then find the area of shaded region

In the given figure, ABCD is a trapezium with AB||CD nad /_BCD=60^(@) .If BFEC is a sector of a circle with centre C and AB=BC=7 cm and DE=4cm , then find the area of the shaded region. [Use pi=22//7 and sqrt(3)=1.73 ]

In the figure, ABCD is a trapezium with AB||DC, and angle ABC = 90^(@) . BCFE is a quadrant of a circle. If BC = CD = 4.2 cm and AE = 18 cm, find the area of the shaded region.

In the figure,AB is a diameter of the circle with centre O and OA=7cm. Find the area of the shaded region

In figure, OACB is a quadrant of a circle with centre O and radius 7 cm. If AD = 2 cm, find the area of the shaded region.

Combination of quadrilateral and circle : In Figure; ABCD is a trapezium with AB||DC ; AB = 18cm; DC = 32cm and the distance between AB and DC is 14 cm. Circles of Equal radii 7 cm with centres A;B;C and D have been drawn. Then; find the area of the shaded region of the figure.

In fig.O is the center of a circle such that diameter AB=13cm and AC=12cm.BC is joined.Find the area of the shaded region.

In Figure 6,O is the centre of the circle with AC=24cm,AB=7cm and /_BOD=90. Find the area of the shaded region.[Use pi=314]

In figure , O is the centre of a circle such that diameter AB= 13 cm and AC = 12 cm . BC is joined .find the area of the shaded region .

From a thin metallic sheet in the shape of a trapezium ABCD in which AB ||CD and angle BCD = 90^(@) , a quarter circle BFEC is removed. Given AB = BC = 3.5 cm and DE = 2cm . Calculate the area of shaded region.

In Fig. 12-34, O is the centre of a circle such that diameter AB=13 cm and AC=12 cm. BC is joined. Find the area of the shaded region.