In any `DeltaABC` (i)`tan((B-C)/2)=((b-c)/(b+c))cot(A/2)` (ii) `tan((A-B)/2)=((a-b)/(a+b))cot(C/2)` (iii)`tan((C-A)/2)=((c-a)/(c+a))cot(B/2)`

In triangle ABC ,prove that tan(B-C)/(2)=(b-c)/(b+c)cot(A)/(2)tan(C-A)/(2)=(c-a)/(c+a)cot(B)/(2)tan(A-B)/(2)=(a-b)/(a+b)cot(C)/(2)

In triangle ABC,, prove that (tan(B-C))/(2),=[(b-c)/(b+c)](cot A)/(2)(tan(C-A))/(2),=[(c-a)/(c+a)](cot B)/(2)(tan(A-B))/(2),=[(a-b)/(a+b)](cot B)/(2)

In a Delta ABC, prove that tan((A+B)/(2))=cot((c)/(2))

cot((A)/(2))+cot((B)/(2))+cot((C)/(2))=cot((A)/(2))cot((B)/(2))cot((C)/(2))

In a Delta ABC prove that (tan(A+B))/(2)=(cot C)/(2)

In any Delta ABC, porve that (a+b-c)cot((B)/(2))=(a-b+c)cot((C)/(2))

In any DeltaABC, sum (b - c) cot A/2 =

Prove that in triangle ABC “tan”(B-C)/2=(b-c)/(b+c)”cot” A/2

In any Delta ABC, prove that (b+c-a)(cot,(B)/(2)+cot,(C)/(2))=2a cot,(A)/(2)

In triangle ABC , prove that tan((C-A)/(2))=((c-a)/(c+a))cot(B)/(2) .