(i)If `3sinx+4cosax=7` has atleast one solution; find the possible values of a. (ii) Solve `cos^50x-sin^50=1`

If 3sin x+4cos ax=7 has at least one solution,then find the possible values of a.

Solve cos^(50)x-sin^(50)x=1

Solve cos^(50) x- sin^(50)x=1

x^(2)+4+3cos(ax+b)=2x has atleast on solution then the value of a+b is :

The equation sinx+x cos x=0 has atleast one root in the interval.

Solve cos 7x= sin 3x

If a, b ∈ [0,2pi] and the equation x^(2) + 4+3sin(ax+b)=2x has atleast one solution, and the least (+ve) . Value of a+b is k then,

0 le a le 3, 0 le b le 3 and the equation, x^(2)+4+3 cos ( ax+b) = 2x has atleast one solution, then find the value of (a+b) .