" Prom that "sqrt(5)" is ivetional "

The simplest rationalising factor of sqrt(3)+sqrt(5) is sqrt(3)-5( b) 3-sqrt(5)(c)sqrt(3)-sqrt(5)(d)sqrt(3)+sqrt(5)

The simplest rationalising factor of sqrt(3)+\ sqrt(5) is (a) sqrt(3)-5 (b) 3-sqrt(5) (c) sqrt(3)-sqrt(5) (d) sqrt(3)+\ sqrt(5)

(sqrt(5)+sqrt(3))((3sqrt(3))/(sqrt(5)+sqrt(2))-sqrt(5)/(sqrt(3)+sqrt(2))) is equal to :

(sqrt(5)-1)/(sqrt(5)+1)+(sqrt(5)+1)/(sqrt(5)-1) =a+b sqrt(5) Then find the value of a and b

sqrt(5+sqrt(5+sqrt(5)))+......oo is equal to

The value of the determinant Delta=|(sqrt(13)+sqrt3,2sqrt5,sqrt5),(sqrt(15)+sqrt(26),5,sqrt(10)),(3+sqrt(65),sqrt(15),5)| is equal to

The value of sqrt(5 sqrt(5 sqrt(5)...)) is