Boys and Girls standing in a queue

Three boys and two girls stand in a queue.The probability,that the number of boys ahead is at least one more than the number of girls ahead of her,is (A) (1)/(2)(B)(1)/(3)(C)(2)/(3)(D)(3)/(4)

Let n be the number of ways in which 5 boys and 5 girls can stand in a queue in such a way that all the girls stand consecutively in the queue.Let m be the number of ways in which 5 boys and 5 girls can stand in a queue in such a way that exactly four girls stand consecutively in the queue.Then the value of m/n is

Let n be the number of ways in which 5 boys and 5 girls can stand in a queue in such a way that all the girls stand consecutively in the queue.Let m be the number in which 5 boys and 5 girls stand in such a way that exactly four girls stand consecutively in the queue. Then the value of (m)/(n) is

Four boys and three girls stand in a queue for an interview,probability that they will in alternate position is

In how many ways can 6 persons stand in a queue?

In how many ways can 6persons stand in a queue?

In how many ways can 6persons stand in a queue?

In how many ways can 5 children stand in a queue?